Vigenre Cip

Ctf

Secconquals2017

Crypto

Ch

[SecconQuals 2016] Vigenere Cipher Write Up

Task information

From the task information we have:

1. len(key) = 12
2. alphabet = ‘ABCDEFGHIJKLMNOPQRSTUVWXYZ{}’
3. md5(plaintext) = f528a6ab914c1ecf856a1d93103948fe

Base on ‘SECCON{’ we can quick calculate key[:7]. Let’s do some quick script to find key[:7]

and we can find key[:7] = ‘VIGENER’

( key[:7] = decode_vigenere(cipher[:7],format_flag),alpha)

Base on the name of the challenge we can guess that key[:8] is ‘VIGENERE’

But len(key) = 12 and md5(plain) = f528a6ab914c1ecf856a1d93103948fe

Now we brute-forcing 4 last chars and start the decryption, if the plain we recieved is valid with md5(plain) = f528a6ab914c1ecf856a1d93103948fe it’s our flag

Here’s my script: solve.py